-16x^2+64x+936=0

Solution for -16x^2+64x+936=0 equation:

-16x^2+64x+936=0

a = -16; b = 64; c = +936;
Δ = b2-4ac
Δ = 642-4·(-16)·936
Δ = 64000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{64000}=\sqrt{6400*10}=\sqrt{6400}*\sqrt{10}=80\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-80\sqrt{10}}{2*-16}=\frac{-64-80\sqrt{10}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+80\sqrt{10}}{2*-16}=\frac{-64+80\sqrt{10}}{-32}
$